What is 3/x+2/y = 9/x*y, 9/x+4/y =(21)/x*y ?

The solution to 3/x+2/y = 9/x*y, 9/x+4/y =(21)/x*y is

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3/x+2/y = 9/xy, 9/x+4/y =(21)/xy

\frac{3}{x} + \frac{2}{y} = \frac{9}{x} \cdot y, \frac{9}{x} + \frac{4}{y} = \frac{21}{x} \cdot y

(x = 3, y = 1)

Solution steps

[\frac{3}{x} + \frac{2}{y} = \frac{9}{x} y \frac{9}{x} + \frac{4}{y} = \frac{21}{x} y]

Isolate

x

for

\frac{3}{x} + \frac{2}{y} = \frac{9}{x} \cdot y : x = \frac{9 y ^{2} - 3 y}{2}

Plug the solutions

x = \frac{9 y ^{2} - 3 y}{2}

into

\frac{9}{x} + \frac{4}{y} = \frac{21}{x} \cdot y

For

\frac{9}{x} + \frac{4}{y} = \frac{21}{x} \cdot y

, subsitute

x

with

\frac{9 y ^{2} - 3 y}{2} : y = 1

Plug the solutions

y = 1

into

\frac{3}{x} + \frac{2}{y} = \frac{9}{x} \cdot y

For

\frac{3}{x} + \frac{2}{y} = \frac{9}{x} \cdot y

, subsitute

y

with

1 : x = 3

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{3}{x} + \frac{2}{y} = \frac{9}{x} \cdot y, \frac{9}{x} + \frac{4}{y} = \frac{21}{x} \cdot y

(x = 3, y = 1)

3 x + y = 2, 3 x + 2 y = 7

(x - 7)^{2} = 3 y, x = 0

\frac{1}{7} x + \frac{1}{6} y = 3, \frac{1}{2} x - \frac{1}{3} y = 5

3 x + y = 7, 4 x + 3 y = 6

x - 4 y = 2, 0.8 - 3 x + 6 y = - 2.4

What is 3/x+2/y = 9/x*y, 9/x+4/y =(21)/x*y ?
The solution to 3/x+2/y = 9/x*y, 9/x+4/y =(21)/x*y is