What is (2a-1)*x+3y=5,3x+(b-1)*y=15 ?

The solution to (2a-1)*x+3y=5,3x+(b-1)*y=15 is

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(2a-1)x+3y=5,3x+(b-1)y=15

(2 a - 1) \cdot x + 3 y = 5, 3 x + (b - 1) \cdot y = 15

(x = \frac{5 ( - b + 10 )}{8 + b + 2 a - 2 ab}, y = - \frac{30 a - 30}{8 + b + 2 a - 2 ab})

Solution steps

[(2 a - 1) x + 3 y = 5 3 x + (b - 1) y = 15]

Isolate

x

for

(2 a - 1) \cdot x + 3 y = 5 : x = \frac{5 - 3 y}{2 a - 1}; a \neq = \frac{1}{2}

Plug the solutions

x = \frac{5 - 3 y}{2 a - 1}

into

3 x + (b - 1) \cdot y = 15

For

3 x + (b - 1) \cdot y = 15

, subsitute

x

with

\frac{5 - 3 y}{2 a - 1} : y = - \frac{30 a - 30}{8 + b + 2 a - 2 ab}; a \neq = \frac{1}{2}, a \neq = \frac{- b - 8}{2 ( 1 - b )}

Plug the solutions

y = - \frac{30 a - 30}{8 + b + 2 a - 2 ab}

into

(2 a - 1) \cdot x + 3 y = 5

For

(2 a - 1) \cdot x + 3 y = 5

, subsitute

y

with

- \frac{30 a - 30}{8 + b + 2 a - 2 ab} : x = \frac{5 ( - b + 10 )}{8 + b + 2 a - 2 ab}; a \neq = \frac{1}{2}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

(2 a - 1) \cdot x + 3 y = 5, 3 x + (b - 1) \cdot y = 15

(x = \frac{5 ( - b + 10 )}{8 + b + 2 a - 2 ab}, y = - \frac{30 a - 30}{8 + b + 2 a - 2 ab})

x + y = 4, 2 x = 5 y

5 x - 2 y = 16, 2 x - 3 y = 13

5 x - 7 y - 3 = 2, x - 4 y + 5 = 0

4 x - y = 9, 2 x - 3 y = - 23

2 x - y = 2, y - x = 2

What is (2a-1)*x+3y=5,3x+(b-1)*y=15 ?
The solution to (2a-1)*x+3y=5,3x+(b-1)*y=15 is