What is x+y+z=-4,2x-y+z=1 ?

The solution to x+y+z=-4,2x-y+z=1 is x=(-2z+9)/3-4,y=-(z+9)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x+y+z=-4,2x-y+z=1

x + y + z = - 4, 2 x - y + z = 1

x = \frac{- 2 z + 9}{3} - 4, y = - \frac{z + 9}{3}

Solution steps

[x + y + z = - 4 2 x - y + z = 1]

Isolate

x

for

x + y + z = - 4 : x = - 4 - y - z

Substitute

x = - 4 - y - z

[2 (- 4 - y - z) - y + z = 1]

Simplify

[- 3 y - z - 8 = 1]

Isolate

y

for

- 3 y - z - 8 = 1 : y = - \frac{z + 9}{3}

For

x = - 4 - y - z

Expressing

x

in terms of

z

x = - 4 - (- \frac{z + 9}{3}) - z

Simplify

- 4 - (- \frac{z + 9}{3}) - z : \frac{- 2 z + 9}{3} - 4

x = \frac{- 2 z + 9}{3} - 4

The solutions to the system of equations are:

x = \frac{- 2 z + 9}{3} - 4, y = - \frac{z + 9}{3}

23 x + 29 y = 98, 29 x + 23 y = 110

4 x + 6 y = 12, 2 x + 3 y = 6

101 x + 99 y = 30, 199 x + 101 y = 299

2 x + 3 y = 5, 3 x - 2 y = 1

3 x + y = 4, 4 x + 2 y = 3

What is x+y+z=-4,2x-y+z=1 ?
The solution to x+y+z=-4,2x-y+z=1 is x=(-2z+9)/3-4,y=-(z+9)/3