What is 7x-5y=15,3x-y=12 ?

The solution to 7x-5y=15,3x-y=12 is x= 45/8 ,y= 39/8

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7x-5y=15,3x-y=12

7 x - 5 y = 15, 3 x - y = 12

x = \frac{45}{8}, y = \frac{39}{8}

Solution steps

[7 x - 5 y = 15 3 x - y = 12]

Isolate

x

for

7 x - 5 y = 15 : x = \frac{15 + 5 y}{7}

Substitute

x = \frac{15 + 5 y}{7}

[3 \cdot \frac{15 + 5 y}{7} - y = 12]

Simplify

[\frac{45 + 8 y}{7} = 12]

Isolate

y

for

\frac{45 + 8 y}{7} = 12 : y = \frac{39}{8}

For

x = \frac{15 + 5 y}{7}

Substitute

y = \frac{39}{8}

x = \frac{15 + 5 \cdot \frac{39}{8}}{7}

\frac{15 + 5 \cdot \frac{39}{8}}{7} = \frac{45}{8}

x = \frac{45}{8}

The solutions to the system of equations are:

x = \frac{45}{8}, y = \frac{39}{8}

x - y + 2 = 2, x - 5 y + 1 = 0

x + y = 2, 2 x + y = 5

3 x - 4 y = 7, 2 x + 5 y = 18

o = 40, s = 6

y - 2 x = 0, y + x = 3