What are the solutions to the equation 2t^2-11t+5=0 ?

The solutions to the equation 2t^2-11t+5=0 are t=5,t= 1/2

Find the zeros of 2t^2-11t+5=0

The zeros of 2t^2-11t+5=0 are t=5,t= 1/2

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2 t^{2} - 11 t + 5 = 0

t = 5, t = \frac{1}{2}

Decimal Notation

t = 5, t = 0.5

Solution steps

2 t^{2} - 11 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 \cdot 5 = 9

t_{1, 2} = \frac{- ( - 11 ) \pm 9}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 11 ) + 9}{2 \cdot 2}, t_{2} = \frac{- ( - 11 ) - 9}{2 \cdot 2}

t = \frac{- ( - 11 ) + 9}{2 \cdot 2} : 5

t = \frac{- ( - 11 ) - 9}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

t = 5, t = \frac{1}{2}

y (x + 1) - 3 (x + 1)

\frac{x}{2} = 22

\frac{2 x ^{2} - 4 x - 16}{x - 4}

- 25 z + 1 + 35 z = 10 z + 1

- (9)^{2}

What are the solutions to the equation 2t^2-11t+5=0 ?
The solutions to the equation 2t^2-11t+5=0 are t=5,t= 1/2
Find the zeros of 2t^2-11t+5=0
The zeros of 2t^2-11t+5=0 are t=5,t= 1/2