What is 33x+20g(x,y)=1,2x-6y=1 ?

The solution to 33x+20g(x,y)=1,2x-6y=1 is x=(6y+1)/2 ,g=-(198y+31)/(40)

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33x+20g(x,y)=1,2x-6y=1

33 x + 20 g (x, y) = 1, 2 x - 6 y = 1

x = \frac{6 y + 1}{2}, g = - \frac{198 y + 31}{40}

Solution steps

[33 x + 20 g = 1 2 x - 6 y = 1]

Isolate

x

for

33 x + 20 g = 1 : x = \frac{1 - 20 g}{33}

Substitute

x = \frac{1 - 20 g}{33}

[2 \cdot \frac{1 - 20 g}{33} - 6 y = 1]

Simplify

[\frac{2 ( 1 - 20 g )}{33} - 6 y = 1]

Isolate

g

for

\frac{2 ( 1 - 20 g )}{33} - 6 y = 1 : g = - \frac{198 y + 31}{40}

For

x = \frac{1 - 20 g}{33}

Expressing

x

in terms of

y

x = \frac{1 - 20 ( - \frac{198 y + 31}{40} )}{33}

Simplify

\frac{1 - 20 ( - \frac{198 y + 31}{40} )}{33} : \frac{6 y + 1}{2}

x = \frac{6 y + 1}{2}

The solutions to the system of equations are:

x = \frac{6 y + 1}{2}, g = - \frac{198 y + 31}{40}

2 x + 4 y = 10, 3 x + 6 y = 12

- 3 x + 6 y = - 3, 5 x - 10 y = 5

6 x = 2, y + 93 x + 4 y = 12

x + 4 = 1, 4 x - y = - 4

2 \frac{x}{3} - \frac{3}{4} = 1, \frac{1}{8} y - \frac{5}{6} x = 2

What is 33x+20g(x,y)=1,2x-6y=1 ?
The solution to 33x+20g(x,y)=1,2x-6y=1 is x=(6y+1)/2 ,g=-(198y+31)/(40)