What is f(x)=x^2-2x+3,f(x)=-2x+19 ?

The solution to f(x)=x^2-2x+3,f(x)=-2x+19 is

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f(x)=x^2-2x+3,f(x)=-2x+19

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 19

(x = 4, x = - 4, f = 11 f = 27)

Solution steps

[f = x^{2} - 2 x + 3 f = - 2 x + 19]

Subtract the equations

f = x^{2} - 2 x + 3

f - f = x^{2} - 2 x + 3 - (- 2 x + 19)

Simplify

0 = x^{2} - 16

Solve

0 = x^{2} - 16 : x = 4, x = - 4

Plug the solutions

x = 4, x = - 4

into

f = x^{2} - 2 x + 3

For

f = x^{2} - 2 x + 3

, subsitute

x

with

4 : f = 11

For

f = x^{2} - 2 x + 3

, subsitute

x

with

- 4 : f = 27

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

f = x^{2} - 2 x + 3, f = - 2 x + 19

are

(x = 4, x = - 4, f = 11 f = 27)

\frac{( x + y )}{( x - y )} + \frac{( x - y )}{( x + y )} = \frac{13}{6}, x y = 5

x^{2} + y^{2} = 2, 5 y x + y - 1 = 0

x + y = 2, x (x - y) = 12

x^{2} + y^{2} = 2, 6 y = 3 - 2 x

x - 3 y = 6, x - 3 y = 4

What is f(x)=x^2-2x+3,f(x)=-2x+19 ?
The solution to f(x)=x^2-2x+3,f(x)=-2x+19 is