What is -x^2y=x+3,y=9 ?

The solution to -x^2y=x+3,y=9 is

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-x^2y=x+3,y=9

- x^{2} y = x + 3, y = 9

(x = - \frac{1}{18} - i \frac{107}{18}, x = - \frac{1}{18} + i \frac{107}{18}, y = 9 y = 9)

Solution steps

[- x^{2} y = x + 3 y = 9]

Plug the solutions

y = 9

into

- x^{2} y = x + 3

For

- x^{2} y = x + 3

, subsitute

y

with

9 : x = - \frac{1}{18} - i \frac{107}{18}, x = - \frac{1}{18} + i \frac{107}{18}

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

- x^{2} y = x + 3, y = 9

are

(x = - \frac{1}{18} - i \frac{107}{18}, x = - \frac{1}{18} + i \frac{107}{18}, y = 9 y = 9)

x + y = 9, x + y = 5

f (x) = x^{2} - 2 x + 3, f (x) = - x + 5

2 x - 3 y = 9, 2 x - 3 y = 13

56 x^{2} - x = 11, 5 y^{2} + 8 y + 1 = 0

x + y = 2, x^{5} + y^{5} = 82