What is x-y=9,x*y=14 ?

The solution to x-y=9,x*y=14 is

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x-y=9,x*y=14

x - y = 9, x \cdot y = 14

(x = 9 + \frac{- 9 + 137}{2}, x = 9 + \frac{- 9 - 137}{2}, y = \frac{- 9 + 137}{2} y = \frac{- 9 - 137}{2})

Solution steps

[x - y = 9 x y = 14]

Isolate

x

for

x - y = 9 : x = 9 + y

Plug the solutions

x = 9 + y

into

x \cdot y = 14

For

x \cdot y = 14

, subsitute

x

with

9 + y : y = \frac{- 9 + 137}{2}, y = \frac{- 9 - 137}{2}

Plug the solutions

y = \frac{- 9 + 137}{2}, y = \frac{- 9 - 137}{2}

into

x - y = 9

For

x - y = 9

, subsitute

y

with

\frac{- 9 + 137}{2} : x = 9 + \frac{- 9 + 137}{2}

For

x - y = 9

, subsitute

y

with

\frac{- 9 - 137}{2} : x = 9 + \frac{- 9 - 137}{2}

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

x - y = 9, x \cdot y = 14

are

(x = 9 + \frac{- 9 + 137}{2}, x = 9 + \frac{- 9 - 137}{2}, y = \frac{- 9 + 137}{2} y = \frac{- 9 - 137}{2})

3 y + 43 = - 2, 5 x^{8} y - 12 x = 32

\frac{( a + 1 )}{5} = 1, \frac{6}{( b + 2 )} = c

x^{2} = 23 x + y, y^{2} = 23 x + y

x^{2} + (y - 1) 2 = 13, 2 x + 3 y = 3

x + y = 1, x^{2} - 2 x + 3 y = - 1