What is y^2=9x,x-y+2=0 ?

The solution to y^2=9x,x-y+2=0 is

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y^2=9x,x-y+2=0

y^{2} = 9 x, x - y + 2 = 0

(x = 4, x = 1, y = 6 y = 3)

Solution steps

[y^{2} = 9 x x - y + 2 = 0]

Isolate

x

for

x - y + 2 = 0 : x = y - 2

Plug the solutions

x = y - 2

into

y^{2} = 9 x

For

y^{2} = 9 x

, subsitute

x

with

y - 2 : y = 6, y = 3

Plug the solutions

y = 6, y = 3

into

x - y + 2 = 0

For

x - y + 2 = 0

, subsitute

y

with

6 : x = 4

For

x - y + 2 = 0

, subsitute

y

with

3 : x = 1

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

y^{2} = 9 x, x - y + 2 = 0

are

(x = 4, x = 1, y = 6 y = 3)

7 x + 2 y + 5 = 0, - 7 x - 2 y + 70 = 0

0.8 \frac{m}{s ^{2}} s = 2.5 u, a = 9

x^{2} - x - 3 x + 3 = 0, y^{2} - 3 y + 2 = 0

t^{2} y = 4 t, x = 2

6^{b} = 8 4^{c}, 1 4^{a} = 3