What is x+y=7,x+z=4x+y+z ?

The solution to x+y=7,x+z=4x+y+z is x=-7/2 ,y= 21/2

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x+y=7,x+z=4x+y+z

x + y = 7, x + z = 4 x + y + z

x = - \frac{7}{2}, y = \frac{21}{2}

Solution steps

[x + y = 7 x + z = 4 x + y + z]

Isolate

x

for

x + y = 7 : x = 7 - y

Substitute

x = 7 - y

[7 - y + z = 4 (7 - y) + y + z]

Simplify

[7 - y + z = 28 - 3 y + z]

Isolate

y

for

7 - y + z = 28 - 3 y + z : y = \frac{21}{2}

For

x = 7 - y

Substitute

y = \frac{21}{2}

x = 7 - \frac{21}{2}

7 - \frac{21}{2} = - \frac{7}{2}

x = - \frac{7}{2}

The solutions to the system of equations are:

x = - \frac{7}{2}, y = \frac{21}{2}

x + y = 10, x y = 16

4 y^{2} - 34 y + 289 = 0, x^{2} = 6

x^{2} + y^{2} - 12 x + 26 = 0, \frac{( x ^{2} )}{2} - y^{2} = \frac{7}{2}

x + y + x y = - 11, x^{2} + y^{2} + x y = 13

x - y - 4 = 0, x y - 12 = 0