What is x-y-4=0,xy-12=0 ?

The solution to x-y-4=0,xy-12=0 is

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x-y-4=0,xy-12=0

x - y - 4 = 0, x y - 12 = 0

(x = 6, x = - 2, y = 2 y = - 6)

Solution steps

[x - y - 4 = 0 x y - 12 = 0]

Isolate

x

for

x - y - 4 = 0 : x = y + 4

Plug the solutions

x = y + 4

into

x y - 12 = 0

For

x y - 12 = 0

, subsitute

x

with

y + 4 : y = 2, y = - 6

Plug the solutions

y = 2, y = - 6

into

x - y - 4 = 0

For

x - y - 4 = 0

, subsitute

y

with

2 : x = 6

For

x - y - 4 = 0

, subsitute

y

with

- 6 : x = - 2

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

x - y - 4 = 0, x y - 12 = 0

are

(x = 6, x = - 2, y = 2 y = - 6)

35 x^{2} - 12 x + 1 = 0, 20 y^{2} - 14 y + 2 = 0

y^{2} x - 7 y = 10, x = 6

x y = 4, 2 x + 3 y = 14

5 \frac{x}{6} - \frac{y}{4} = - 2, 3 r + 2 n = 3

y - 17 = x^{2} - 9 x, - x + y = 1