What is 35x^2-12x+1=0,20y^2-14y+2=0 ?

The solution to 35x^2-12x+1=0,20y^2-14y+2=0 is

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35x^2-12x+1=0,20y^2-14y+2=0

35 x^{2} - 12 x + 1 = 0, 20 y^{2} - 14 y + 2 = 0

x = \frac{1}{7}, x = \frac{1}{7}, x = \frac{1}{5}, x = \frac{1}{5}, y = \frac{1}{2} y = \frac{1}{5} y = \frac{1}{2} y = \frac{1}{5}

Solution steps

[35 x^{2} - 12 x + 1 = 0 20 y^{2} - 14 y + 2 = 0]

Solve

35 x^{2} - 12 x + 1 = 0 : x = \frac{1}{7}, x = \frac{1}{5}

For

20 y^{2} - 14 y + 2 = 0

, subsitute

x

with

\frac{1}{7} : y = \frac{1}{2}, y = \frac{1}{5}

For

20 y^{2} - 14 y + 2 = 0

, subsitute

x

with

\frac{1}{5} : y = \frac{1}{2}, y = \frac{1}{5}

Solve

20 y^{2} - 14 y + 2 = 0 : y = \frac{1}{5}, y = \frac{1}{2}

For

35 x^{2} - 12 x + 1 = 0

, subsitute

y

with

\frac{1}{5} : x = \frac{1}{5}, x = \frac{1}{7}

For

35 x^{2} - 12 x + 1 = 0

, subsitute

y

with

\frac{1}{2} : x = \frac{1}{5}, x = \frac{1}{7}

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

35 x^{2} - 12 x + 1 = 0, 20 y^{2} - 14 y + 2 = 0

are

x = \frac{1}{7}, x = \frac{1}{7}, x = \frac{1}{5}, x = \frac{1}{5}, y = \frac{1}{2} y = \frac{1}{5} y = \frac{1}{2} y = \frac{1}{5}

y^{2} x - 7 y = 10, x = 6

x y = 4, 2 x + 3 y = 14

5 \frac{x}{6} - \frac{y}{4} = - 2, 3 r + 2 n = 3

y - 17 = x^{2} - 9 x, - x + y = 1

a = \frac{81}{3 ^{3}} - x y, b = 2^{3} - x y

What is 35x^2-12x+1=0,20y^2-14y+2=0 ?
The solution to 35x^2-12x+1=0,20y^2-14y+2=0 is