What is 4x^2-9(y+1)^2=36,2x+3y=-5 ?

The solution to 4x^2-9(y+1)^2=36,2x+3y=-5 is

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4x^2-9(y+1)^2=36,2x+3y=-5

4 x^{2} - 9 (y + 1)^{2} = 36, 2 x + 3 y = - 5

(x = - 5, y = \frac{5}{3})

Solution steps

[4 x^{2} - 9 (y + 1)^{2} = 36 2 x + 3 y = - 5]

Isolate

x

for

2 x + 3 y = - 5 : x = \frac{- 5 - 3 y}{2}

Plug the solutions

x = \frac{- 5 - 3 y}{2}

into

4 x^{2} - 9 (y + 1)^{2} = 36

For

4 x^{2} - 9 (y + 1)^{2} = 36

, subsitute

x

with

\frac{- 5 - 3 y}{2} : y = \frac{5}{3}

Plug the solutions

y = \frac{5}{3}

into

2 x + 3 y = - 5

For

2 x + 3 y = - 5

, subsitute

y

with

\frac{5}{3} : x = - 5

Verify solutions by plugging them into the original equations

Therefore, the final solution for

4 x^{2} - 9 (y + 1)^{2} = 36, 2 x + 3 y = - 5

(x = - 5, y = \frac{5}{3})

x^{2} - 25 = 0, y^{3} = 216

y^{2} = 89, x = 88

y x + 6 = 9, x + y = 6

x + y - 10 = 0, e x^{2} + y^{2} + 18 x - 2 y = 0

x^{2} + y^{2} = 1, 8 y = - x + 6

What is 4x^2-9(y+1)^2=36,2x+3y=-5 ?
The solution to 4x^2-9(y+1)^2=36,2x+3y=-5 is