What is x^2-25=0,y^3=216 ?

The solution to x^2-25=0,y^3=216 is

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x^2-25=0,y^3=216

x^{2} - 25 = 0, y^{3} = 216

x = - 5, x = - 5, x = - 5, x = 5, x = 5, x = 5, y = 6 y = - 3 + 33 i y = - 3 - 33 i y = 6 y = - 3 + 33 i y = - 3 - 33 i

Solution steps

[x^{2} - 25 = 0 y^{3} = 216]

Solve

x^{2} - 25 = 0 : x = - 5, x = 5

For

y^{3} = 216

, subsitute

x

with

- 5 : y = 6, y = - 3 + 33 i, y = - 3 - 33 i

For

y^{3} = 216

, subsitute

x

with

5 : y = 6, y = - 3 + 33 i, y = - 3 - 33 i

Solve

y^{3} = 216 : y = 6, y = - 3 + 33 i, y = - 3 - 33 i

For

x^{2} - 25 = 0

, subsitute

y

with

6 : x = 5, x = - 5

For

x^{2} - 25 = 0

, subsitute

y

with

- 3 + 33 i : x = 5, x = - 5

For

x^{2} - 25 = 0

, subsitute

y

with

- 3 - 33 i : x = 5, x = - 5

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

x^{2} - 25 = 0, y^{3} = 216

are

x = - 5, x = - 5, x = - 5, x = 5, x = 5, x = 5, y = 6 y = - 3 + 33 i y = - 3 - 33 i y = 6 y = - 3 + 33 i y = - 3 - 33 i

y^{2} = 89, x = 88

y x + 6 = 9, x + y = 6

x + y - 10 = 0, e x^{2} + y^{2} + 18 x - 2 y = 0

x^{2} + y^{2} = 1, 8 y = - x + 6

x + y = 1, 7 x^{2} + y^{2} = 1 3^{2}