What are the solutions to the equation 8x^2+2=5x^2 ?

The solutions to the equation 8x^2+2=5x^2 are x=sqrt(2/3)i,x=-sqrt(2/3)i

Find the zeros of 8x^2+2=5x^2

The zeros of 8x^2+2=5x^2 are x=sqrt(2/3)i,x=-sqrt(2/3)i

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8 x^{2} + 2 = 5 x^{2}

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

8 x^{2} + 2 = 5 x^{2}

Move

2

to the right side

8 x^{2} = 5 x^{2} - 2

Move

5 x^{2}

to the left side

3 x^{2} = - 2

Divide both sides by

3

x^{2} = - \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{2}{3}, x = - - \frac{2}{3}

- \frac{2}{3} = \frac{2}{3} i

- - \frac{2}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

u^{2} - 13 = - 36

- 4 x^{2} + 8 x + 44 = 16

x y - x z - y w + z w

7 y - 2 (8 y + 1) = 4

3 - 4 y < 12

What are the solutions to the equation 8x^2+2=5x^2 ?
The solutions to the equation 8x^2+2=5x^2 are x=sqrt(2/3)i,x=-sqrt(2/3)i
Find the zeros of 8x^2+2=5x^2
The zeros of 8x^2+2=5x^2 are x=sqrt(2/3)i,x=-sqrt(2/3)i