What is 1/x+4/y = 2/7 , 4/3 x+1/2 y=-8/5 ?

The solution to 1/x+4/y = 2/7 , 4/3 x+1/2 y=-8/5 is

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1/x+4/y = 2/7 , 4/3 x+1/2 y=-8/5

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}, \frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}

(x = \frac{21}{20}, x = - 4, y = - 6 y = \frac{112}{15})

Solution steps

[\frac{1}{x} + \frac{4}{y} = \frac{2}{7} \frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}]

Isolate

x

for

\frac{1}{x} + \frac{4}{y} = \frac{2}{7} : x = - \frac{7 y}{2 ( 14 - y )}; y \neq = 14

Plug the solutions

x = - \frac{7 y}{2 ( 14 - y )}

into

\frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}

For

\frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}

, subsitute

x

with

- \frac{7 y}{2 ( 14 - y )} : y = - 6, y = \frac{112}{15}

Plug the solutions

y = - 6, y = \frac{112}{15}

into

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}

For

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}

, subsitute

y

with

- 6 : x = \frac{21}{20}

For

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}

, subsitute

y

with

\frac{112}{15} : x = - 4

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}, \frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}

are

(x = \frac{21}{20}, x = - 4, y = - 6 y = \frac{112}{15})

f (x) (x)^{1} (x) = 1, + x f (x) (x)^{2} (x) = x^{2}

x + 3 y = 13, x^{2} + 3 y^{2} = 43

u (y, x) - 9 u (y, x) = (\frac{1}{2}) x^{4}, y = 6

0 + \frac{1}{2} yy = x + 150, x = 15

x + y = 12, \frac{1}{x} + \frac{1}{y} = 8

What is 1/x+4/y = 2/7 , 4/3 x+1/2 y=-8/5 ?
The solution to 1/x+4/y = 2/7 , 4/3 x+1/2 y=-8/5 is