What is u(y,x)-9u(y,x)=(1/2)x^4,y=6 ?

The solution to u(y,x)-9u(y,x)=(1/2)x^4,y=6 is No Solution

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u(y,x)-9u(y,x)=(1/2)x^4,y=6

u (y, x) - 9 u (y, x) = (\frac{1}{2}) x^{4}, y = 6

No Solution

Solution steps

[u - 9 u = (\frac{1}{2}) x^{4} y = 6]

Solve

u - 9 u = (\frac{1}{2}) x^{4}

for

y = 6 : (x \in R, y = 6, u = - \frac{x ^{4}}{16})

Verify solutions by plugging them into the original equations

No Solution

0 + \frac{1}{2} yy = x + 150, x = 15

x + y = 12, \frac{1}{x} + \frac{1}{y} = 8

8 x + (- 2 a + b - 4) = 4 y, - 6 x + (a - b + 2) y + 9 = 0

3 x y + 2 y^{2} = 5, x y - 3 y^{2} = - 57

x - x^{2} y = x - 2, y = 2

What is u(y,x)-9u(y,x)=(1/2)x^4,y=6 ?
The solution to u(y,x)-9u(y,x)=(1/2)x^4,y=6 is No Solution