What is f(x)=2,x^2+8x-3x^0=-3 ?

The solution to f(x)=2,x^2+8x-3x^0=-3 is

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f(x)=2,x^2+8x-3x^0=-3

f (x) = 2, x^{2} + 8 x - 3 x^{0} = - 3

(x = - 8, f = 2)

Solution steps

[f = 2 x^{2} + 8 x - 3 x^{0} = - 3]

Solve

x^{2} + 8 x - 3 x^{0} = - 3 : x = 0, x = - 8

For

f = 2

, subsitute

x

with

0 : f = 2

For

f = 2

, subsitute

x

with

- 8 : f = 2

Verify solutions by plugging them into the original equations

Therefore, the final solution for

f = 2, x^{2} + 8 x - 3 x^{0} = - 3

(x = - 8, f = 2)

2 x^{3} y = 1, 0.93 x y = 1.1

8 x^{4} - 3 y = 17, 7 x - 4 y = 8

x - y = - 6, x^{2} - y = - 4

6 x^{2} + 7 x - 3 = 0, x_{1} = x_{2}

x - y = 2, 2 x^{2} + 9 y^{2} = 23