What is -3x^2+8x+35>0 ?

The solution to -3x^2+8x+35>0 is -7/3 <x<5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-3x^2+8x+35>0

- 3 x^{2} + 8 x + 35 > 0

- \frac{7}{3} < x < 5

Interval Notation

(- \frac{7}{3}, 5)

Decimal Notation

- 2.33333 \dots < x < 5

Solution steps

- 3 x^{2} + 8 x + 35 > 0

Factor

- 3 x^{2} + 8 x + 35 : - (3 x + 7) (x - 5)

- (3 x + 7) (x - 5) > 0

Multiply both sides by

- 1

(reverse the inequality)

(- (3 x + 7) (x - 5)) (- 1) < 0 \cdot (- 1)

Simplify

(3 x + 7) (x - 5) < 0

Identify the intervals

- \frac{7}{3} < x < 5

\frac{4}{( 3 x + 2 )} \geq 0

2 x^{2} - 7 x + 7 > 0

(x + 5) (2 x - 3)^{5} (x - 7)^{3} \cdot (3 x + 8)^{2} < 0

(2 x - 3)^{2} > (2 x + 5) (2 x - 1)

\frac{1}{( x + 1 )} + \frac{2}{( x + 3 )} > \frac{3}{( x + 2 )}