What is (x-1)(x+2)-(x+2)(x-3)>0 ?

The solution to (x-1)(x+2)-(x+2)(x-3)>0 is x>-2

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(x-1)(x+2)-(x+2)(x-3)>0

(x - 1) (x + 2) - (x + 2) (x - 3) > 0

x > - 2

Interval Notation

(- 2, \infty)

Solution steps

(x - 1) (x + 2) - (x + 2) (x - 3) > 0

Rewrite in standard form

x + 2 > 0

Move

2

to the right side

x > - 2

\frac{( 2 x - 3 )}{( 3 x - 5 )} \geq 3

x^{2} - 3 x + 4 > 0

\frac{( x + 2 )}{( x - 1 )} < 4

\frac{( 7 - 2 k )}{( 4 ( - k ) )} \leq 1

\frac{( 2 ( x - 4 ) )}{( ( x - 1 ) ( x - 7 ) )} \leq \frac{1}{( x - 2 )}

What is (x-1)(x+2)-(x+2)(x-3)>0 ?
The solution to (x-1)(x+2)-(x+2)(x-3)>0 is x>-2