What is 1/((x+1)-1)>= (2-1)/((x-2)) ?

The solution to 1/((x+1)-1)>= (2-1)/((x-2)) is 0<x<2

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1/((x+1)-1)>= (2-1)/((x-2))

\frac{1}{( x + 1 ) - 1} \geq \frac{2 - 1}{( x - 2 )}

0 < x < 2

Interval Notation

(0, 2)

Solution steps

\frac{1}{x + 1 - 1} \geq \frac{2 - 1}{x - 2}

Rewrite in standard form

\frac{1}{x ( x - 2 )} \leq 0

\frac{1}{a} \leq 0

then

a < 0

x (x - 2) < 0

Identify the intervals

0 < x < 2

4 (m + 2)^{2} + 4 (m + 2) (3 m - 1) \leq 0

x^{3} + 3 x^{2} + 5 x + 3 \geq 0

\frac{( 36 x - 7 )}{( 2 + 3 x )} \geq 12

(x^{2} - 9)^{2} \cdot (x + 1) (x^{2} - 2 x - 3) (x - 1) \leq 0

- x^{3} + x \leq 0

What is 1/((x+1)-1)>= (2-1)/((x-2)) ?
The solution to 1/((x+1)-1)>= (2-1)/((x-2)) is 0<x<2