What is ((36x-7))/((2+3x))>= 12 ?

The solution to ((36x-7))/((2+3x))>= 12 is x<-2/3

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((36x-7))/((2+3x))>= 12

\frac{( 36 x - 7 )}{( 2 + 3 x )} \geq 12

x < - \frac{2}{3}

Interval Notation

(- \infty, - \frac{2}{3})

Decimal Notation

x < - 0.66666 \dots

Solution steps

\frac{36 x - 7}{2 + 3 x} \geq 12

Rewrite in standard form

\frac{1}{2 + 3 x} \leq 0

\frac{1}{a} \leq 0

then

a < 0

2 + 3 x < 0

Move

2

to the right side

3 x < - 2

Divide both sides by

3

x < - \frac{2}{3}

(x^{2} - 9)^{2} \cdot (x + 1) (x^{2} - 2 x - 3) (x - 1) \leq 0

- x^{3} + x \leq 0

\frac{( x ^{2} + 4 ) ( x - 2 )}{( x - 3 )} < 0

\frac{12 x}{x - 4} \geq \frac{6 x}{x + 6}

- 2 x^{2} + x - 1 < 0

What is ((36x-7))/((2+3x))>= 12 ?
The solution to ((36x-7))/((2+3x))>= 12 is x<-2/3