What is 48+2x-x^2>= 0 ?

The solution to 48+2x-x^2>= 0 is -6<= x<= 8

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48+2x-x^2>= 0

48 + 2 x - x^{2} \geq 0

- 6 \leq x \leq 8

Interval Notation

[- 6, 8]

Solution steps

48 + 2 x - x^{2} \geq 0

Factor

48 + 2 x - x^{2} : - (x + 6) (x - 8)

- (x + 6) (x - 8) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x + 6) (x - 8)) (- 1) \leq 0 \cdot (- 1)

Simplify

(x + 6) (x - 8) \leq 0

Identify the intervals

- 6 \leq x \leq 8

\frac{5}{6 ( x + 2 ) - 4} < \frac{x}{3 + 12}

3 \cdot (x - 1)^{2} - 12 \leq 6 x^{2} - (3 + x)^{2}

\frac{( ( x + 1 ) ^{2} + 1 )}{x} > 0

\frac{( x ^{2} - 5 x + 4 )}{( x ^{2} - 1 )} \leq 1

x (x + 2) - x^{2} > 4 x - 7