What is 3*(x-1)^2-12<= 6x^2-(3+x)^2 ?

The solution to 3*(x-1)^2-12<= 6x^2-(3+x)^2 is True for all x

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3*(x-1)^2-12<= 6x^2-(3+x)^2

3 \cdot (x - 1)^{2} - 12 \leq 6 x^{2} - (3 + x)^{2}

True for all x

Interval Notation

(- \infty, \infty)

Solution steps

3 (x - 1)^{2} - 12 \leq 6 x^{2} - (3 + x)^{2}

Rewrite in standard form

- x^{2} \leq 0

Multiply both sides by

- 1

x^{2} \geq 0

If n is even,

u^{n} \geq 0

for all

u

True for all x

\frac{( ( x + 1 ) ^{2} + 1 )}{x} > 0

\frac{( x ^{2} - 5 x + 4 )}{( x ^{2} - 1 )} \leq 1

x (x + 2) - x^{2} > 4 x - 7

\frac{( 6 + j ^{3} )}{( 2 - j ^{3} ) + 8} < \frac{3}{10}

x^{2} - 2 x - 4 \leq 0

What is 3*(x-1)^2-12<= 6x^2-(3+x)^2 ?
The solution to 3*(x-1)^2-12<= 6x^2-(3+x)^2 is True for all x