What is the answer to 3(2x+1)-(x+1)/2 = 1/2 [x+2-(x+1)/3 ] ?

The answer to 3(2x+1)-(x+1)/2 = 1/2 [x+2-(x+1)/3 ] is x=-10/31

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3(2x+1)-(x+1)/2 = 1/2 [x+2-(x+1)/3 ]

3 (2 x + 1) - \frac{x + 1}{2} = \frac{1}{2} [x + 2 - \frac{x + 1}{3}]

x = - \frac{10}{31}

Decimal Notation

x = - 0.32258 \dots

Solution steps

3 (2 x + 1) - \frac{x + 1}{2} = \frac{1}{2} [x + 2 - \frac{x + 1}{3}]

Expand

3 (2 x + 1) - \frac{x + 1}{2} : \frac{11 x}{2} - \frac{1}{2} + 3

Expand

\frac{1}{2} (x + 2 - \frac{x + 1}{3}) : \frac{x}{3} + \frac{5}{6}

\frac{11 x}{2} - \frac{1}{2} + 3 = \frac{x}{3} + \frac{5}{6}

Multiply by LCM

33 x + 15 = 2 x + 5

Move

15

to the right side

33 x = 2 x - 10

Move

2 x

to the left side

31 x = - 10

Divide both sides by

31

x = - \frac{10}{31}

∣ 1 - 7 x ∣ + 5 \geq 8

y^{2} - 10 y = - 14

f - 4 = 6 f + 26

9 < - 3 m < 24

(x + 2) (x + 3)

What is the answer to 3(2x+1)-(x+1)/2 = 1/2 [x+2-(x+1)/3 ] ?
The answer to 3(2x+1)-(x+1)/2 = 1/2 [x+2-(x+1)/3 ] is x=-10/31
Solve for x: 3(2x+1)-(x+1)/2 = 1/2 [x+2-(x+1)/3 ]
The solution is x=-10/31