What is ((2x+1))/((x-5))<= 3 ?

The solution to ((2x+1))/((x-5)) = 16

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((2x+1))/((x-5))<= 3

\frac{( 2 x + 1 )}{( x - 5 )} \leq 3

x < 5 or x \geq 16

Interval Notation

(- \infty, 5) \cup [16, \infty)

Solution steps

\frac{2 x + 1}{x - 5} \leq 3

Rewrite in standard form

\frac{- x + 16}{x - 5} \leq 0

Identify the intervals

x < 5 or x \geq 16

2 x^{2} - x + 5 > 0

- x^{3} + 3 x^{2} - 2 x > 0

\frac{1}{( x + 4 )} \leq \frac{- 1}{6}

\frac{( ( x - 4 ) ( x - 3 ) )}{( x - 3 )} \leq 0

\frac{( 14 x )}{( x + 1 )} - \frac{( 9 x - 30 )}{( x - 4 )} < 0

What is ((2x+1))/((x-5))<= 3 ?
The solution to ((2x+1))/((x-5))<= 3 is x<5\lor x>= 16