en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/((2x+1))>0

Solution

\frac{1}{( 2 x + 1 )} > 0

Solution

x > - \frac{1}{2}

+2

Interval Notation

(- \frac{1}{2}, \infty)

Decimal Notation

x > - 0.5

Solution steps

\frac{1}{2 x + 1} > 0

If

\frac{1}{a} > 0

then

a > 0

2 x + 1 > 0

Move

1

to the right side

2 x > - 1

Divide both sides by

2

x > - \frac{1}{2}

Popular Examples

2 x^{2} - 2 x + 3 > 0

((2-3x))/((3-2x))>= 0

\frac{( 2 - 3 x )}{( 3 - 2 x )} \geq 0

((x+4))/((x^2+4x+4))>((x-2))/((x^2-4))

\frac{( x + 4 )}{( x ^{2} + 4 x + 4 )} > \frac{( x - 2 )}{( x ^{2} - 4 )}

(a^2)/((a^4+1))>= 1/2

\frac{a ^{2}}{( a ^{4} + 1 )} \geq \frac{1}{2}

x^3-4x^2+2<x^3-2x^2+1

x^{3} - 4 x^{2} + 2 < x^{3} - 2 x^{2} + 1

Frequently Asked Questions (FAQ)

What is 1/((2x+1))>0 ?
The solution to 1/((2x+1))>0 is x>-1/2