What are the solutions to the equation 4x^2+x=0 ?

The solutions to the equation 4x^2+x=0 are x=0,x=-1/4

Find the zeros of 4x^2+x=0

The zeros of 4x^2+x=0 are x=0,x=-1/4

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4 x^{2} + x = 0

x = 0, x = - \frac{1}{4}

Solution steps

4 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

1^{2} - 4 \cdot 4 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 \cdot 4}, x_{2} = \frac{- 1 - 1}{2 \cdot 4}

x = \frac{- 1 + 1}{2 \cdot 4} : 0

x = \frac{- 1 - 1}{2 \cdot 4} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{4}

- 8 < - 2 z + 4 < 10

- \frac{3}{4} (x + 2) = 6

x^{2} - x - 9 = 0

- \frac{0.9 ( 10 )}{( 0.01 ( 10 ) ^{2} + 1 ) ^{2}}

4 x^{2} - 14 x - 8 = 0

What are the solutions to the equation 4x^2+x=0 ?
The solutions to the equation 4x^2+x=0 are x=0,x=-1/4
Find the zeros of 4x^2+x=0
The zeros of 4x^2+x=0 are x=0,x=-1/4