-3x-2x<-9

Solution

- 3 x - 2 x < - 9

x > \frac{9}{5}

Interval Notation

(\frac{9}{5}, \infty)

Decimal Notation

x > 1.8

Solution steps

- 3 x - 2 x < - 9

Add similar elements:

- 3 x - 2 x = - 5 x

- 5 x < - 9

Multiply both sides by

- 1

5 x > 9

Divide both sides by

5

x > \frac{9}{5}

10 \frac{( x + 1 )}{2} + 10 \frac{( x + 3 )}{5} > 10 \frac{( 6 x - 1 )}{10}

\frac{( 1 - lo g _{4} ( x ) )}{( 1 + lo g _{2} ( x ) )} \leq \frac{1}{2}

\frac{( 3 x + 1 )}{7} - \frac{( 2 - 4 x )}{3} \geq \frac{( - 5 x - 4 )}{14} + \frac{( 7 x )}{6}

x - 4 < 4

\frac{x}{2 + 1} > x