What is log_{10}(8)(3x-10)< 1/3 ?

The solution to log_{10}(8)(3x-10)< 1/3 is x<(1+90log_{10}(2))/(27log_{10)(2)}

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log_{10}(8)(3x-10)< 1/3

lo g_{10} (8) (3 x - 10) < \frac{1}{3}

x < \frac{1 + 90 lo g _{10} ( 2 )}{27 lo g _{10} ( 2 )}

Interval Notation

(- \infty, \frac{1 + 90 lo g _{10} ( 2 )}{27 lo g _{10} ( 2 )})

Decimal Notation

x < 3.45636 \dots

Solution steps

lo g_{10} (8) (3 x - 10) < \frac{1}{3}

Simplify

lo g_{10} (8) : 3 lo g_{10} (2)

3 lo g_{10} (2) (3 x - 10) < \frac{1}{3}

Divide both sides by

3 lo g_{10} (2)

3 x - 10 < \frac{1}{9 lo g _{10} ( 2 )}

Move

10

to the right side

3 x < \frac{1}{9 lo g _{10} ( 2 )} + 10

Divide both sides by

3

x < \frac{1 + 90 lo g _{10} ( 2 )}{27 lo g _{10} ( 2 )}

x, 8 x - 5 y < 3

d, (d) \frac{( x + 1 )}{( ( x - 1 ) ^{2} )} < 1

x - 2 < \frac{10 + x}{2}

15 - (3 x - 2) < 18 - (x + 4)

7 x < 2 x + 100

What is log_{10}(8)(3x-10)< 1/3 ?
The solution to log_{10}(8)(3x-10)< 1/3 is x<(1+90log_{10}(2))/(27log_{10)(2)}