What are the solutions to the equation 4x^2-2x=0 ?

The solutions to the equation 4x^2-2x=0 are x= 1/2 ,x=0

Find the zeros of 4x^2-2x=0

The zeros of 4x^2-2x=0 are x= 1/2 ,x=0

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4 x^{2} - 2 x = 0

x = \frac{1}{2}, x = 0

Solution steps

4 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 2)^{2} - 4 \cdot 4 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 4}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 4}

x = \frac{- ( - 2 ) + 2}{2 \cdot 4} : \frac{1}{2}

x = \frac{- ( - 2 ) - 2}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 0

9 y^{6} + 6 y^{4} + y^{2}

4 x \leq - 12

\frac{3}{2} - \frac{1}{4}

40 x^{2} - 1400 x + 12000 = 0

3^{\frac{5}{3}}

What are the solutions to the equation 4x^2-2x=0 ?
The solutions to the equation 4x^2-2x=0 are x= 1/2 ,x=0
Find the zeros of 4x^2-2x=0
The zeros of 4x^2-2x=0 are x= 1/2 ,x=0