What are the solutions to the equation 9v^2+25=-30v ?

The solutions to the equation 9v^2+25=-30v are v=-5/3

Find the zeros of 9v^2+25=-30v

The zeros of 9v^2+25=-30v are v=-5/3

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9 v^{2} + 25 = - 30 v

v = - \frac{5}{3}

Solution steps

9 v^{2} + 25 = - 30 v

Move

30 v

to the left side

9 v^{2} + 25 + 30 v = 0

Write in the standard form

a x^{2} + b x + c = 0

9 v^{2} + 30 v + 25 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 9 \cdot 25}{2 \cdot 9}

3 0^{2} - 4 \cdot 9 \cdot 25 = 0

v_{1, 2} = \frac{- 30 \pm 0}{2 \cdot 9}

v = \frac{- 30}{2 \cdot 9}

\frac{- 30}{2 \cdot 9} = - \frac{5}{3}

v = - \frac{5}{3}

The solution to the quadratic equation is:

v = - \frac{5}{3}

\frac{ln ( 2 )}{0.03}

- 84 = 6 (4 a - 6)

- 6 x^{2} - 4 x + 2 = 0

- 45 x^{3} - 5 x^{2}

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What are the solutions to the equation 9v^2+25=-30v ?
The solutions to the equation 9v^2+25=-30v are v=-5/3
Find the zeros of 9v^2+25=-30v
The zeros of 9v^2+25=-30v are v=-5/3