What is (25(|x+3|+x))/((x+2))>1 ?

The solution to (25(|x+3|+x))/((x+2))>1 is -77 -73/49

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(25(|x+3|+x))/((x+2))>1

\frac{25 ( ∣ x + 3 ∣ + x )}{( x + 2 )} > 1

- 77 < x < - 2 or x > - \frac{73}{49}

Interval Notation

(- 77, - 2) \cup (- \frac{73}{49}, \infty)

Decimal Notation

- 77 < x < - 2 or x > - 1.48979 \dots

Solution steps

\frac{25 ( ∣ x + 3 ∣ + x )}{x + 2} > 1

Find positive and negative intervals

x < - 3, x \geq - 3

Solve the inequality for each interval

- 77 < x < - 3 or - 3 \leq x < - 2 or x > - \frac{73}{49}

Merge Overlapping Intervals

- 77 < x < - 2 or x > - \frac{73}{49}

x + 2 - x^{2} \leq x^{2} - 3 x + 4

(\frac{( ∣ x + 1 ∣ + 5 )}{∣ 2 - x ∣}) > 5

∣ 2 x + 4.5 ∣ > ∣ x - 2.7 ∣

x, f > - ∣ x - 2 ∣ + 4

(a) ∣ x - 2 ∣ \leq ∣ x + 4 ∣

What is (25(|x+3|+x))/((x+2))>1 ?
The solution to (25(|x+3|+x))/((x+2))>1 is -77<x<-2\lor x>-73/49