What is x^2-3|x|-10<0 ?

The solution to x^2-3|x|-10<0 is -5<x<5

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x^2-3|x|-10<0

x^{2} - 3 ∣ x ∣ - 10 < 0

- 5 < x < 5

Interval Notation

(- 5, 5)

Solution steps

x^{2} - 3 ∣ x ∣ - 10 < 0

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

- 5 < x < 0 or 0 \leq x < 5

Merge Overlapping Intervals

- 5 < x < 5

∣ 3 t - 4 ∣ < 8

∣ 6 x - 12 ∣ < ∣ 2 - x ∣

\frac{3 x}{( x ^{2} - 4 )} \leq 1

x^{2} - 9 + x^{2} - 1 > 8

11 x - 9 < 3 x + 11 < 7 x + 13