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Popular >

4|6-x|+2>= 10

Solution

4 ∣ 6 - x ∣ + 2 \geq 10

Solution

x \leq 4 or x \geq 8

+1

Solution steps

4 ∣ 6 - x ∣ + 2 \geq 10

Move

2

to the right side

4 ∣ 6 - x ∣ \geq 8

Divide both sides by

4

∣ 6 - x ∣ \geq 2

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

6 - x \leq - 2 or 6 - x \geq 2

6 - x \leq - 2 or 6 - x \geq 2

x \leq 4 or x \geq 8

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(\frac{12 a ^{3} b ^{5}}{4 a ^{6} b ^{3}})^{3}

Frequently Asked Questions (FAQ)

What is 4|6-x|+2>= 10 ?
The solution to 4|6-x|+2>= 10 is x<= 4\lor x>= 8