What are the solutions to the equation x^2-x-17=0 ?

The solutions to the equation x^2-x-17=0 are x=(1+sqrt(69))/2 ,x=(1-sqrt(69))/2

Find the zeros of x^2-x-17=0

The zeros of x^2-x-17=0 are x=(1+sqrt(69))/2 ,x=(1-sqrt(69))/2

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x^{2} - x - 17 = 0

x = \frac{1 + 69}{2}, x = \frac{1 - 69}{2}

Decimal Notation

x = 4.65331 \dots, x = - 3.65331 \dots

Solution steps

x^{2} - x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 17) = 69

x_{1, 2} = \frac{- ( - 1 ) \pm 69}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 69}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 69}{2 \cdot 1}

x = \frac{- ( - 1 ) + 69}{2 \cdot 1} : \frac{1 + 69}{2}

x = \frac{- ( - 1 ) - 69}{2 \cdot 1} : \frac{1 - 69}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 69}{2}, x = \frac{1 - 69}{2}

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What are the solutions to the equation x^2-x-17=0 ?
The solutions to the equation x^2-x-17=0 are x=(1+sqrt(69))/2 ,x=(1-sqrt(69))/2
Find the zeros of x^2-x-17=0
The zeros of x^2-x-17=0 are x=(1+sqrt(69))/2 ,x=(1-sqrt(69))/2