What are the solutions to the equation 60x^2+113x-63=0 ?

The solutions to the equation 60x^2+113x-63=0 are x= 9/20 ,x=-7/3

Find the zeros of 60x^2+113x-63=0

The zeros of 60x^2+113x-63=0 are x= 9/20 ,x=-7/3

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60 x^{2} + 113 x - 63 = 0

x = \frac{9}{20}, x = - \frac{7}{3}

Decimal Notation

x = 0.45, x = - 2.33333 \dots

Solution steps

60 x^{2} + 113 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 113 \pm 11 3 ^{2} - 4 \cdot 60 ( - 63 )}{2 \cdot 60}

11 3^{2} - 4 \cdot 60 (- 63) = 167

x_{1, 2} = \frac{- 113 \pm 167}{2 \cdot 60}

Separate the solutions

x_{1} = \frac{- 113 + 167}{2 \cdot 60}, x_{2} = \frac{- 113 - 167}{2 \cdot 60}

x = \frac{- 113 + 167}{2 \cdot 60} : \frac{9}{20}

x = \frac{- 113 - 167}{2 \cdot 60} : - \frac{7}{3}

The solutions to the quadratic equation are:

x = \frac{9}{20}, x = - \frac{7}{3}

(\frac{2}{5} a b^{3})^{3}

\frac{3 x - 1}{2} = \frac{5 x - 4}{3}

10 x^{2} + 23 x = 21

8^{7}

6 (3 x + 5) = 5 (8 x + 6)

What are the solutions to the equation 60x^2+113x-63=0 ?
The solutions to the equation 60x^2+113x-63=0 are x= 9/20 ,x=-7/3
Find the zeros of 60x^2+113x-63=0
The zeros of 60x^2+113x-63=0 are x= 9/20 ,x=-7/3