What are the solutions to the equation 10x^2+23x=21 ?

The solutions to the equation 10x^2+23x=21 are x= 7/10 ,x=-3

Find the zeros of 10x^2+23x=21

The zeros of 10x^2+23x=21 are x= 7/10 ,x=-3

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10 x^{2} + 23 x = 21

x = \frac{7}{10}, x = - 3

Solution steps

10 x^{2} + 23 x = 21

Move

21

to the left side

10 x^{2} + 23 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 10 ( - 21 )}{2 \cdot 10}

2 3^{2} - 4 \cdot 10 (- 21) = 37

x_{1, 2} = \frac{- 23 \pm 37}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 23 + 37}{2 \cdot 10}, x_{2} = \frac{- 23 - 37}{2 \cdot 10}

x = \frac{- 23 + 37}{2 \cdot 10} : \frac{7}{10}

x = \frac{- 23 - 37}{2 \cdot 10} : - 3

The solutions to the quadratic equation are:

x = \frac{7}{10}, x = - 3

8^{7}

6 (3 x + 5) = 5 (8 x + 6)

(3 - 2 i) + (- 2 + 7 i)

34 c^{2} d^{2} f^{3} - 17 c^{5} d^{4} - 51 f c^{4}

2 x^{1} + 3 x^{2} = 2

What are the solutions to the equation 10x^2+23x=21 ?
The solutions to the equation 10x^2+23x=21 are x= 7/10 ,x=-3
Find the zeros of 10x^2+23x=21
The zeros of 10x^2+23x=21 are x= 7/10 ,x=-3