What is 0<= 2x-3/4-3x<= 1 ?

The solution to 0<= 2x-3/4-3x<= 1 is -7/4 <= x<=-3/4

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0<= 2x-3/4-3x<= 1

0 \leq 2 x - \frac{3}{4} - 3 x \leq 1

- \frac{7}{4} \leq x \leq - \frac{3}{4}

Interval Notation

[- \frac{7}{4}, - \frac{3}{4}]

Decimal Notation

- 1.75 \leq x \leq - 0.75

Solution steps

0 \leq 2 x - \frac{3}{4} - 3 x \leq 1

a \leq u \leq b

then

a \leq u and u \leq b

0 \leq 2 x - \frac{3}{4} - 3 x and 2 x - \frac{3}{4} - 3 x \leq 1

0 \leq 2 x - \frac{3}{4} - 3 x : x \leq - \frac{3}{4}

2 x - \frac{3}{4} - 3 x \leq 1 : x \geq - \frac{7}{4}

Combine the intervals

x \leq - \frac{3}{4} and x \geq - \frac{7}{4}

Merge Overlapping Intervals

- \frac{7}{4} \leq x \leq - \frac{3}{4}

- 7 < 3 x + 2 \leq 5

- 3 < 2 + 4 x < 12

\frac{( 2 ^{1 - x} - 2 ^{x} + 1 )}{( 2 ^{x} - 1 )} \leq 0

2^{x} + 2^{- x + 1} - 3 < 0

(\frac{3}{2})^{1 + x^{2}} > (\frac{2}{3})^{3 x - 1}

What is 0<= 2x-3/4-3x<= 1 ?
The solution to 0<= 2x-3/4-3x<= 1 is -7/4 <= x<=-3/4