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Popular >

log_{2}(x+1)<2

Solution

lo g_{2} (x + 1) < 2

Solution

- 1 < x < 3

+1

Interval Notation

(- 1, 3)

Solution steps

lo g_{2} (x + 1) < 2

Apply log rules

x + 1 < 4 and x + 1 > 0

x + 1 < 4 and x + 1 > 0 : - 1 < x < 3

- 1 < x < 3

Popular Examples

k>= ((log_{10}(n)))/((log_{10)(2))}

k \geq \frac{( lo g _{10} ( n ) )}{( lo g _{10} ( 2 ) )}

log_{x+4}(5x+20)<= log_{x+4}((x+4)^2)

lo g_{x + 4} (5 x + 20) \leq lo g_{x + 4} ((x + 4)^{2})

log_{x}(x^2-4x+4)>= 0

lo g_{x} (x^{2} - 4 x + 4) \geq 0

log_{7}(((2x-6))/((2x-1)))>0

lo g_{7} (\frac{( 2 x - 6 )}{( 2 x - 1 )}) > 0

(log_{0.5}(x))^2+log_{0.5}(x)-2<= 0

(lo g_{0.5} (x))^{2} + lo g_{0.5} (x) - 2 \leq 0

Frequently Asked Questions (FAQ)

What is log_{2}(x+1)<2 ?
The solution to log_{2}(x+1)<2 is -1<x<3