What is ((log_{2}(x+1)))/((x-1))>0 ?

The solution to ((log_{2}(x+1)))/((x-1))>0 is -1 1

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((log_{2}(x+1)))/((x-1))>0

\frac{( lo g _{2} ( x + 1 ) )}{( x - 1 )} > 0

- 1 < x < 0 or x > 1

Interval Notation

(- 1, 0) \cup (1, \infty)

Solution steps

\frac{lo g _{2} ( x + 1 )}{x - 1} > 0

Identify the intervals

- 1 < x < 0 or x > 1

lo g_{3} (x^{2} - 8 x) < 2

lo g_{2} (1 + x^{- 1}) + lo g_{\frac{1}{2}} (\frac{1 + x}{4}) \geq 1

x - ln (x) > 0

2 \geq 1 + ln (b)

lo g_{6} (x^{2}) \geq lo g_{6} (9)

What is ((log_{2}(x+1)))/((x-1))>0 ?
The solution to ((log_{2}(x+1)))/((x-1))>0 is -1<x<0\lor x>1