What is longdivision ((x^2-3))/((x^2+2x-4)) ?

The solution to longdivision ((x^2-3))/((x^2+2x-4)) is 1+(-2x+1)/(x^2+2x-4)

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longdivision ((x^2-3))/((x^2+2x-4))

long division

\frac{( x ^{2} - 3 )}{( x ^{2} + 2 x - 4 )}

1 + \frac{- 2 x + 1}{x ^{2} + 2 x - 4}

Solution steps

\frac{( x ^{2} - 3 )}{( x ^{2} + 2 x - 4 )}

Divide

\frac{x ^{2} - 3}{x ^{2} + 2 x - 4} : \frac{x ^{2} - 3}{x ^{2} + 2 x - 4} = 1 + \frac{- 2 x + 1}{x ^{2} + 2 x - 4}

= 1 + \frac{- 2 x + 1}{x ^{2} + 2 x - 4}

\frac{( 1 - x )}{( 1 + x )}

\frac{( x ^{13} + 1 )}{( x - 1 )}

\frac{( x + 2 )}{( x - 2 )}

\frac{( 3 x ^{3} - 2 x ^{2} + 7 x - 5 )}{( x + 3 )}

\frac{( n + 1 )}{( n - 1 )}

What is longdivision ((x^2-3))/((x^2+2x-4)) ?
The solution to longdivision ((x^2-3))/((x^2+2x-4)) is 1+(-2x+1)/(x^2+2x-4)