What is longdivision (6x^3+3x^2-5)/(3x^2+1) ?

The solution to longdivision (6x^3+3x^2-5)/(3x^2+1) is 2x+1+(-2x-6)/(3x^2+1)

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longdivision (6x^3+3x^2-5)/(3x^2+1)

long division

\frac{6 x ^{3} + 3 x ^{2} - 5}{3 x ^{2} + 1}

2 x + 1 + \frac{- 2 x - 6}{3 x ^{2} + 1}

Solution steps

\frac{6 x ^{3} + 3 x ^{2} - 5}{3 x ^{2} + 1}

Divide

\frac{6 x ^{3} + 3 x ^{2} - 5}{3 x ^{2} + 1} : \frac{6 x ^{3} + 3 x ^{2} - 5}{3 x ^{2} + 1} = 2 x + \frac{3 x ^{2} - 2 x - 5}{3 x ^{2} + 1}

= 2 x + \frac{3 x ^{2} - 2 x - 5}{3 x ^{2} + 1}

Divide

\frac{3 x ^{2} - 2 x - 5}{3 x ^{2} + 1} : \frac{3 x ^{2} - 2 x - 5}{3 x ^{2} + 1} = 1 + \frac{- 2 x - 6}{3 x ^{2} + 1}

= 2 x + 1 + \frac{- 2 x - 6}{3 x ^{2} + 1}

\frac{x ^{2} + 4 x - 1}{x + 2}

\frac{( x ^{2} - 1 )}{( x - 9 )}

\frac{( 243 x ^{5} - 1 )}{( 3 x + 1 )}

\frac{( x ^{2} + 1 )}{( x + 1 )}

\frac{( 4 x ^{3} - 2 x ^{2} + 2 x - 1 )}{( 2 x + 1 )}

What is longdivision (6x^3+3x^2-5)/(3x^2+1) ?
The solution to longdivision (6x^3+3x^2-5)/(3x^2+1) is 2x+1+(-2x-6)/(3x^2+1)