What is longdivision ((x^2+1))/((x+1)) ?

The solution to longdivision ((x^2+1))/((x+1)) is x-1+2/(x+1)

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longdivision ((x^2+1))/((x+1))

long division

\frac{( x ^{2} + 1 )}{( x + 1 )}

x - 1 + \frac{2}{x + 1}

Solution steps

\frac{( x ^{2} + 1 )}{( x + 1 )}

Divide

\frac{x ^{2} + 1}{x + 1} : \frac{x ^{2} + 1}{x + 1} = x + \frac{- x + 1}{x + 1}

= x + \frac{- x + 1}{x + 1}

Divide

\frac{- x + 1}{x + 1} : \frac{- x + 1}{x + 1} = - 1 + \frac{2}{x + 1}

= x - 1 + \frac{2}{x + 1}

\frac{( 4 x ^{3} - 2 x ^{2} + 2 x - 1 )}{( 2 x + 1 )}

\frac{( x ^{4} - x ^{2} + 1 )}{( 1 - x )}

\frac{( 6 a ^{2} - 7 a + 5 )}{( 2 a - 3 )}

\frac{( 2 x ^{2} + 5 x - 7 )}{( x - 2 )}

\frac{( 3 x + 2 )}{( 7 x - 1 )}

What is longdivision ((x^2+1))/((x+1)) ?
The solution to longdivision ((x^2+1))/((x+1)) is x-1+2/(x+1)