What is (8x^2-7x+8)-(4x^2-3x+3) ?

The solution to (8x^2-7x+8)-(4x^2-3x+3) is 4x^2-4x+5

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simplify (8x^2-7x+8)-(4x^2-3x+3)

simplify

(8 x^{2} - 7 x + 8) - (4 x^{2} - 3 x + 3)

4 x^{2} - 4 x + 5

Solution steps

(8 x^{2} - 7 x + 8) - (4 x^{2} - 3 x + 3)

Apply rule:

(a) = a

(8 x^{2} - 7 x + 8) = 8 x^{2} - 7 x + 8

= 8 x^{2} - 7 x + 8 - (4 x^{2} - 3 x + 3)

Apply the distributive law:

- (a - b) = - a + b

- (4 x^{2} - 3 x + 3) = - 4 x^{2} + 3 x - 3

= 8 x^{2} - 7 x + 8 - 4 x^{2} + 3 x - 3

Group like terms

= 8 x^{2} - 4 x^{2} - 7 x + 3 x + 8 - 3

Add similar elements:

8 x^{2} - 4 x^{2} = 4 x^{2}

= 4 x^{2} - 7 x + 3 x + 8 - 3

Add similar elements:

- 7 x + 3 x = - 4 x

= 4 x^{2} - 4 x + 8 - 3

Subtract the numbers:

8 - 3 = 5

= 4 x^{2} - 4 x + 5

(x + 1)^{3} - x^{3} - 3 x^{2}

18 x y + 3 y

(2 x^{2} + 10 x - 2) - (- 8 x^{2} + 7 x + 7)

(- 8 x + 10) - (3 x^{2} - x + 6)

(2 x^{2} - 4) - (- x^{2} + 3 x - 6)

What is (8x^2-7x+8)-(4x^2-3x+3) ?
The solution to (8x^2-7x+8)-(4x^2-3x+3) is 4x^2-4x+5