What are the solutions to the equation x^2-14x-12=0 ?

The solutions to the equation x^2-14x-12=0 are x=7+sqrt(61),x=7-sqrt(61)

Find the zeros of x^2-14x-12=0

The zeros of x^2-14x-12=0 are x=7+sqrt(61),x=7-sqrt(61)

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x^{2} - 14 x - 12 = 0

x = 7 + 61, x = 7 - 61

Decimal Notation

x = 14.81024 \dots, x = - 0.81024 \dots

Solution steps

x^{2} - 14 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 12) = 261

x_{1, 2} = \frac{- ( - 14 ) \pm 2 61}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 61}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 61}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 61}{2 \cdot 1} : 7 + 61

x = \frac{- ( - 14 ) - 2 61}{2 \cdot 1} : 7 - 61

The solutions to the quadratic equation are:

x = 7 + 61, x = 7 - 61

5 x^{2} + 12 x \leq 9

x^{2} + 81 x + 18 = 54

\frac{3}{2} + \frac{2}{5}

3 v + 9 - 8 v = - 31

v^{2} = 9

What are the solutions to the equation x^2-14x-12=0 ?
The solutions to the equation x^2-14x-12=0 are x=7+sqrt(61),x=7-sqrt(61)
Find the zeros of x^2-14x-12=0
The zeros of x^2-14x-12=0 are x=7+sqrt(61),x=7-sqrt(61)