What is 7^{log_{49}(9)-2log_{7}(5)} ?

The solution to 7^{log_{49}(9)-2log_{7}(5)} is 3/25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 7^{log_{49}(9)-2log_{7}(5)}

simplify

7^{l o g_{49} (9) - 2 l o g_{7} (5)}

\frac{3}{25}

Decimal Notation

0.12

Solution steps

7^{l o g_{49} (9) - 2 l o g_{7} (5)}

lo g_{49} (9) - 2 lo g_{7} (5) = lo g_{7} (\frac{3}{25})

= 7^{l o g_{7} (\frac{3}{25})}

Apply log rule:

a^{l o g_{a} (b)} = b

7^{l o g_{7} (\frac{3}{25})} = \frac{3}{25}

= \frac{3}{25}

- 3 - 4 i

\frac{8}{1 - 3 x}

- 10 (9 v - 2 v + 7) - 10 v

(3 p - 2 q + 5) (3 p - 2 q - 5)

x^{4} - 6 x^{3} - 8 x^{2} + 96 x - 128

What is 7^{log_{49}(9)-2log_{7}(5)} ?
The solution to 7^{log_{49}(9)-2log_{7}(5)} is 3/25