What are the solutions to the equation 17x-x^2=52 ?

The solutions to the equation 17x-x^2=52 are x=4,x=13

Find the zeros of 17x-x^2=52

The zeros of 17x-x^2=52 are x=4,x=13

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17 x - x^{2} = 52

x = 4, x = 13

Solution steps

17 x - x^{2} = 52

Move

52

to the left side

17 x - x^{2} - 52 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 17 x - 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 1 ) ( - 52 )}{2 ( - 1 )}

1 7^{2} - 4 (- 1) (- 52) = 9

x_{1, 2} = \frac{- 17 \pm 9}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 17 + 9}{2 ( - 1 )}, x_{2} = \frac{- 17 - 9}{2 ( - 1 )}

x = \frac{- 17 + 9}{2 ( - 1 )} : 4

x = \frac{- 17 - 9}{2 ( - 1 )} : 13

The solutions to the quadratic equation are:

x = 4, x = 13

\frac{4}{6} + \frac{4}{8}

(2 x + 5)^{2} = 49

(u^{5})^{\frac{7}{10}}

\frac{\frac{1}{2}}{π}

cos (arcsin (2 x))

What are the solutions to the equation 17x-x^2=52 ?
The solutions to the equation 17x-x^2=52 are x=4,x=13
Find the zeros of 17x-x^2=52
The zeros of 17x-x^2=52 are x=4,x=13