What is (5x^{-7}yz^{-3})(2x)^4 ?

The solution to (5x^{-7}yz^{-3})(2x)^4 is (80y)/(x^3z^3)

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simplify (5x^{-7}yz^{-3})(2x)^4

simplify

(5 x^{- 7} y z^{- 3}) (2 x)^{4}

\frac{80 y}{x ^{3} z ^{3}}

Solution steps

(5 x^{- 7} y z^{- 3}) (2 x)^{4}

Simplify

5 x^{- 7} y z^{- 3} : \frac{5 y}{x ^{7} z ^{3}}

= \frac{5 y}{x ^{7} z ^{3}} (2 x)^{4}

Simplify

(2 x)^{4} : 16 x^{4}

= \frac{5 y}{x ^{7} z ^{3}} \cdot 16 x^{4}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{5 y \cdot 16 x ^{4}}{x ^{7} z ^{3}}

Simplify

\frac{x ^{4}}{x ^{7}} : \frac{1}{x ^{3}}

= \frac{5 y \cdot 16}{x ^{3} z ^{3}}

Multiply the numbers:

5 \cdot 16 = 80

= \frac{80 y}{x ^{3} z ^{3}}

3 (a + h)^{2}

(4 - y)^{7}

(- 3 x^{2} y^{5})^{2}

(- 5) (4)

What is (5x^{-7}yz^{-3})(2x)^4 ?
The solution to (5x^{-7}yz^{-3})(2x)^4 is (80y)/(x^3z^3)